You need to write out every step of your calculation including Venn Diagram, not just the final answer, in order to receive full credit.
(If you don’t show work, you will get 55% by default).
Q#1: Construct Venn diagram : U=1000
n(A)=520, n(B)=330 & n(A⋂B) =199
Help: Venn Diagram with two sets
Q#2: Construct Venn diagram: U=2550
n(A)=225, n(B)=410, n(C)=356
n(A⋂B) =56, n(B⋂C) =90, n(A⋂C) =110 and n(A⋂B⋂C) = 17
Help: How to Construct Venn Diagram with Three Sets?
Q#3: A college survey was taken to determine which social media platform students use. Of 538 students surveyed, 95 used
Facebook, 78 used Snap-chat, 35 used both the Facebook and Snap-chat. Draw a Venn Diagram then answer the
following;
a. How many used Facebook only?
b. How many used Snap-chat only?
c. How many Facebook or Snap-chat?
d. How many Snap-chat but not Facebook?
e. How many did not used either the Facebook or the Snap-chat?
Help: Solving Application Problems of 2 Sets With Venn Diagram
Q#4: In a survey of four-year colleges, it was found that 318 offered a criminal justice degree. 319 offered Information technology degree. 557 offered a nursing degree. 95 offered a criminal justice degree and Information technology degree.103 offered criminal justice degree and a nursing degree. 95 offered Information technology degree and a nursing degree. 29 offered a criminal justice, Information technology degree, and a nursing degree. 35 offered none of these degrees.
a. How many is criminal justice degree only?
b. How many four-year colleges were surveyed?
c. A criminal justice degree and a nursing degree, but not IT degree?
d. IT degree, but neither a criminal justice degree nor a nursing degree?
e. A criminal justice, IT degree, and a nursing degree?
Help: Solving Venn diagram application problem by three sets
Q#5: Using the data below construct a Venn diagram then answer the following questions.
survey of faculty and graduate students at the University of Hollywood ‘s film school
revealed the following information:
51 admire Moe
49 admire Larry
60 admire Curly
34 admire Moe and Larry
32 admire Larry and Curly
36 admire Moe and Curly
24 admire all three of the Stooges
1 admires none of the Three Stooges
a. How many people were surveyed?
b. How many admire Moe, but not Larry and Curly?
Help: Solving Venn diagram application problem by three sets
Struggling with where to start this assignment? Follow this guide to tackle your assignment easily!
Q#1: Construct a Venn Diagram for Two Sets
Given Data:
- Universal set: U=1000U = 1000
- n(A)=520n(A) = 520 (total in set A)
- n(B)=330n(B) = 330 (total in set B)
- n(A∩B)=199n(A \cap B) = 199 (in both sets A and B)
Step 1: Find the numbers in only A, only B, and neither
- Only in A: n(A only)=n(A)−n(A∩B)=520−199=321n(A \text{ only}) = n(A) – n(A \cap B) = 520 – 199 = 321
- Only in B: n(B only)=n(B)−n(A∩B)=330−199=131n(B \text{ only}) = n(B) – n(A \cap B) = 330 – 199 = 131
- Neither A nor B: n(Neither)=U−(n(A only)+n(B only)+n(A∩B))n(\text{Neither}) = U – (n(A \text{ only}) + n(B \text{ only}) + n(A \cap B)) =1000−(321+131+199)=1000−651=349= 1000 – (321 + 131 + 199) = 1000 – 651 = 349
Final Values for Venn Diagram
- Only A = 321
- Only B = 131
- Both A and B = 199
- Neither A nor B = 349
Q#2: Construct a Venn Diagram for Three Sets
Given Data:
- U=2550U = 2550
- n(A)=225,n(B)=410,n(C)=356n(A) = 225, n(B) = 410, n(C) = 356
- n(A∩B)=56,n(B∩C)=90,n(A∩C)=110n(A \cap B) = 56, n(B \cap C) = 90, n(A \cap C) = 110
- n(A∩B∩C)=17n(A \cap B \cap C) = 17
Step 1: Find the values for individual sections
- Only A: n(A only)=n(A)−(n(A∩B)+n(A∩C)−n(A∩B∩C))n(A \text{ only}) = n(A) – (n(A \cap B) + n(A \cap C) – n(A \cap B \cap C)) =225−(56+110−17)=225−149=76= 225 – (56 + 110 – 17) = 225 – 149 = 76
- Only B: n(B only)=n(B)−(n(A∩B)+n(B∩C)−n(A∩B∩C))n(B \text{ only}) = n(B) – (n(A \cap B) + n(B \cap C) – n(A \cap B \cap C)) =410−(56+90−17)=410−129=281= 410 – (56 + 90 – 17) = 410 – 129 = 281
- Only C: n(C only)=n(C)−(n(A∩C)+n(B∩C)−n(A∩B∩C))n(C \text{ only}) = n(C) – (n(A \cap C) + n(B \cap C) – n(A \cap B \cap C)) =356−(110+90−17)=356−183=173= 356 – (110 + 90 – 17) = 356 – 183 = 173
- Neither A, B, nor C: n(Neither)=U−(n(A only)+n(B only)+n(C only)+n(A∩B)+n(B∩C)+n(A∩C)−2n(A∩B∩C))n(\text{Neither}) = U – (n(A \text{ only}) + n(B \text{ only}) + n(C \text{ only}) + n(A \cap B) + n(B \cap C) + n(A \cap C) – 2n(A \cap B \cap C)) =2550−(76+281+173+56+90+110−2(17))= 2550 – (76 + 281 + 173 + 56 + 90 + 110 – 2(17)) =2550−766=1784= 2550 – 766 = 1784
Final Values for Venn Diagram
- Only A = 76
- Only B = 281
- Only C = 173
- A & B only = 56 – 17 = 39
- B & C only = 90 – 17 = 73
- A & C only = 110 – 17 = 93
- A & B & C = 17
- Neither = 1784
Q#3: College Survey on Social Media Use
Given Data:
- U=538U = 538
- n(Facebook)=95n(Facebook) = 95
- n(Snapchat)=78n(Snapchat) = 78
- n(Facebook∩Snapchat)=35n(Facebook \cap Snapchat) = 35
Step 1: Find the values for individual sections
- Facebook Only: n(FB only)=95−35=60n(FB \text{ only}) = 95 – 35 = 60
- Snapchat Only: n(Snap only)=78−35=43n(Snap \text{ only}) = 78 – 35 = 43
- Neither: n(Neither)=U−(n(FB only)+n(Snap only)+n(Facebook∩Snapchat))n(\text{Neither}) = U – (n(FB \text{ only}) + n(Snap \text{ only}) + n(Facebook \cap Snapchat)) =538−(60+43+35)=538−138=400= 538 – (60 + 43 + 35) = 538 – 138 = 400
Final Answers
- (a) Facebook Only = 60
- (b) Snapchat Only = 43
- (c) Facebook or Snapchat = 138
- (d) Snapchat but not Facebook = 43
- (e) Neither = 400
Q#4: College Degrees
Given Data:
- n(CJ)=318,n(IT)=319,n(N)=557n(CJ) = 318, n(IT) = 319, n(N) = 557
- n(CJ∩IT)=95,n(CJ∩N)=103,n(IT∩N)=95n(CJ \cap IT) = 95, n(CJ \cap N) = 103, n(IT \cap N) = 95
- n(CJ∩IT∩N)=29n(CJ \cap IT \cap N) = 29
- n(None)=35n(\text{None}) = 35
Final Answers
- CJ Only = 318−(95+103−29)=149318 – (95 + 103 – 29) = 149
- Total Colleges Surveyed = 318+319+557−95−103−95+29+35=865318 + 319 + 557 – 95 – 103 – 95 + 29 + 35 = 865
- CJ & Nursing but not IT = 103−29=74103 – 29 = 74
- IT Only = 319−(95+95−29)=158319 – (95 + 95 – 29) = 158
- All Three = 2929
Q#5: Admiration of Three Stooges
Given Data:
- n(M)=51,n(L)=49,n(C)=60n(M) = 51, n(L) = 49, n(C) = 60
- n(M∩L)=34,n(L∩C)=32,n(M∩C)=36n(M \cap L) = 34, n(L \cap C) = 32, n(M \cap C) = 36
- n(M∩L∩C)=24n(M \cap L \cap C) = 24
- n(None)=1n(\text{None}) = 1
Step 1: Find the values for individual sections
- Only Moe: n(M only)=51−(34+36−24)=51−46=5n(M \text{ only}) = 51 – (34 + 36 – 24) = 51 – 46 = 5
Final Answers
- (a) Total People Surveyed = 51+49+60−34−32−36+24+1=12351 + 49 + 60 – 34 – 32 – 36 + 24 + 1 = 123
- (b) Moe Only = 5
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